使用C语言计算两个日期之间间隔了多少分钟的程序

使用C语言计算两个日期之间间隔了多少分钟的方法：

默认计算2000年之后的，否则请改一下year_afer2000 那个地方。
默认计算间隔了多少分钟，若要计算秒钟，需要对应修改一下整体。

#include <stdio.h>
//#include <stdlib.h>
//#include <ctype.h>
//#include <string.h>
//#include <stdio.h>
//#include <time.h>
unsigned long cal_total_min( int year, int month, int day, int hour, int minute )
{unsigned long	total_minutes1;unsigned long	total_minutes2;unsigned long	total_minutes3;unsigned long	total_minutes4;unsigned long	date1_minutes;int year_afer2000;int		i;int		month_days[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };/* 计算日期1到日期2的总分钟数 */total_minutes1 = 0;year_afer2000 = year - 2000;                                /* 默认计算2000年之后的 */for ( i = 0; i < year_afer2000; i++ ){if ( (i % 4 == 0 && i % 100 != 0) || i % 400 == 0 )     /* 闰年 */total_minutes1 += 366 * 24 * 60;elsetotal_minutes1 += 365 * 24 * 60;}total_minutes2 = 0;for ( i = 0; i < month - 1; i++ )if ( i == 1 )                                                           /* 2月 */{if ( (year % 4 == 0 && year % 100 != 0) || year % 400 == 0 )    /* 闰年 */total_minutes2 += 29 * 24 * 60;elsetotal_minutes2 += 28 * 24 * 60;} else {total_minutes2 += month_days[i] * 24 * 60;}total_minutes3	= day * 24 * 60;total_minutes4	= hour * 60 + minute;date1_minutes	= total_minutes1 + total_minutes2 + total_minutes3 + total_minutes4;return(date1_minutes);
}/* 计算两个日期相差多少分钟的绝对值,考虑每个月天数和闰年 */
unsigned long cal_two_time_diff( char *time1, char *time2 )
{int		year1, month1, day1, hour1, minute1;int		year2, month2, day2, hour2, minute2;unsigned long	date1_minutes;unsigned long	date2_minutes;sscanf( time1, "%4d%2d%2d%2d%2d", &year1, &month1, &day1, &hour1, &minute1 );sscanf( time2, "%4d%2d%2d%2d%2d", &year2, &month2, &day2, &hour2, &minute2 );date1_minutes	= cal_total_min( year1, month1, day1, hour1, minute1 );date2_minutes	= cal_total_min( year2, month2, day2, hour2, minute2 );/* 两个日期相差的绝对分钟数 */if ( date1_minutes > date2_minutes )return(date1_minutes - date2_minutes);elsereturn(date2_minutes - date1_minutes);
}int main() {unsigned long diff_minutes = cal_two_time_diff("202312312359", "200001010000");printf("两个日期相差的分钟数为:%lu\\n", diff_minutes);return 0;
}