项目中获取resource下文件路径的方法

String filepath=request.getServletContext().getRealPath("/")+"files\\\\";

获取的当前文件在实际运行的tomcat地址目录

String path = ClassUtils.getDefaultClassLoader().getResource("").getPath()+"tmp/files/";

获取的是当前文件的静态目录

但是以上两种方式在linux或者jar包中会失效，想要在jar包中或者linux下同样获取到文件，可以用下面这种：WORD_TEMPLATE是文件在resource下路径

public String getString() throws IOException {String WORD_TEMPLATE = "/file/2.txt";InputStream io = this.getClass().getResourceAsStream(WORD_TEMPLATE);BufferedReader br = new BufferedReader(new InputStreamReader(io));String line;String result = "";while ((line = br.readLine()) != null) {result = result+" "+line;}br.close();return result.trim();}